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Thread: Some simple pneumatic questions

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    The size of ram or cylinder used in a Flipper and the amount of energy that it could possibly deliver governs the maximum throw of a given mass....you cannot get more but you can get a lot less if your flipper mechanism and pneumatic system isnt matched correctly.

    Acceleration, Velocity and Extension time equations follow for a given ram force and load.

    Force to extend in Kg = 0.008 (constant) * (bore in mm) * (bore in mm) * (pressure in bar)

    So let€™s take a cylinder with a 100mm bore and 200mm stroke @ 20 bar.

    Ram Force = .008 * 100 * 100 * 20 = 1,600kgf

    Mass to move = 100kg @ lets say a 4-1 ratio.

    So the tip is taking 100 kg and moving it over a distance of four times the stroke ( 800 mm ) or 0.8 metre with a force of ...divide ram force of 1,600kg by the lift ratio of 4 ... 400kgf.

    Acceleration = force in Newtons/mass to move

    CONVERT Kgf TO NEWTON€™S (multiply by 9. = 400 x 9.8 = 3,920 Newton€™s of tip force.

    So 3,920 Newton€™s /100 = 39.2 m/sec/sec...then take gravity in to account ...minus gravity 9.8 m/sec/sec = 29.4

    Then calculate the velocity.

    v = SQRT(2as)

    Where a is the acceleration and s is the distance travelled.

    v = SQRT ( 2 * 29.4 * 0.8 )= 6.8 m/sec ...this is a MAXIMUM velocity and no matter how you try you cannot get more ...only less.

    Throw = v*v/2*Gravity

    6.8 * 6.8/19.6 = 2.36 metres above the flipper tip.

    Lets take this MAX velocity of 6.8 m/sec and calculate the ram extension time.

    Solving for time t= V minus Vo /Accel = 6.8/29.4

    Stroke Time (secs) = 0.23 second ..This is the quickest possible extension time for the given ram force and load.

    You should now size your pneumatic system so as to keep a constant pressure under the piston and FILL this ram @ 20 bar in 0.23 sec.

    Ram volume in cc (Convert ram dimensions to centimetres) = Radius * Radius * stroke * Pi.

    5cm * 5cm * 20cm * 3.14 = 1,570 cc or 1.57 litres.

    So to fill the ram in 0.23 of a second we must supply

    1/0.23 * 1.57 litres of gas per second @ 20 bar = 6.82 litres per sec @ 20 bar.

    We need this to be in litres per second @ 1 bar.. so multiply by your working pressure of 20... 136.4 Litres per second.


    Cant be bothered with the Math?
    Theres an embedded calc towards the bottom of my page.
    http://www.teamonslaught.fsnet.co.uk/pneumatics.htm
    http://www.teamonslaught.fsnet.co.uk/pneumatics.htm

    The embedded calc also outputs a Kv and Cv MAXIMUM value recommendation for your valve.

    (Message edited by woody on October 26, 200

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    Ball valves.

    http://www.yateson-stainless.com/yateson03.htm
    http://www.yateson-stainless.com/yateson03.htm

    Scroll down the centre panel for some pdfs.

    Watch out for the opening torque ratings for these ball valves ...youll need a DECENT actuating ram to get the valve to open QUICKLY!

    http://www.valves-online.co.uk/acatalog/Three_Way_Ball_Valve.htmlhttp://www.valves-online.co.uk/acata...all_Valve.html

    (Message edited by woody on October 26, 200

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