If you can't get an opponent OOTA with 10 flips, it will become an endurance fight.
Can your machine drive upside down?
Printable View
If you can't get an opponent OOTA with 10 flips, it will become an endurance fight.
Can your machine drive upside down?
Unfortunately no, worse than that, the way it's designed, when it runs out of Co2 the flipper blade will always be in the open position. So I need to leave some reserve Co2 to keep it closed.Quote:
Originally Posted by maddox10
Better to use spring(bungee) return, that saves gas and gets the flipper in default closed.
The thing is I'll be using a spring as the main force to deploy the flipper the pneumatics to cock the spring. It's still at design stage but before starting the actual build I want to make sure it's within the weight limits
Attachment 6321
Is there a way to calculate what throw would this set up be able to produce?
The pneumatics would run on 55bar.
How free flowing the gas supply is has as much influence as the geometry. Small tank, pipe, regulator and valve will restrict gas flow and you wont get full pressure. The flipper arm mass has a small effect too, as does where the opponent is on the arm. You could get from 30cm to 3m depending on the system efficiency.
Assuming a very light arm and perfect pnuematics:
H = P*(R^2)*T/10/M
H=flip height
P = pressure in pascals
R = cylinder radius in metres
T= cylinder throw in metres
M = opponent mass in kg.
but that will only tell you the upper limit. The pressure drop will be significant.
Let's leave the efficiency of the pneumatics out of the equation for now, what I'm after is the geometry. With a ram stroke of 38mm and a force of approx 1000kg will the geometry work?
I'm wondering if I put too much negative mechanical advantage, and can't figure out how to get approximate figures.
@Mark, your formula seems to do without leverage ratios
The flipperarm will push the extended rod down and lock it, making retracting difficult or even impossible.
It will be pneumatic retract ram Mario so should not be an issue, what do you think in terms of flip height tho?
Going from real life examples with rams in that size range you get this kind of flips.
Starting on 18 seconds.
https://www.youtube.com/watch?v=HM349ORrbq4
I'd prefer to get flips similar to that at 13 seconds ;)
Attachment 6323
So I was going through the forum and found this flipper calculator (I believe you linked it Mario)
I put the figures in and the result looks good for me, honestly too good.
Just to explain the values in the table, I'm not actually using a 68mm bore ram, but two of 52mm - still that does not matter. I'm using the rams to compress two springs, each rated at 1000kg. The only restriction the springs have is against the exhausting air. (which will exit through a 8mm dia QEV - not much restriction)
The total force of the springs is 2000kg, that's why I used a 68mm ram for the calculation as it gives approx 2000kg of force at 55bar.
The springs compress 38mm so that's the stroke and the flipper arm moves 195mm up, that gives a lever ratio of 5.
The calculated throw of almost 6 metres is impressive, even if it's a theoretical maximum! Wish it would be close to even half that figure! :D