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Just for clarrification, the reason the link/ fuse is put in the positive line is that MOSFETs dont like loosing their earth path.
MOSFETs need somewhere for the energy to flow and if you remove this path, it is likely to result in their untimely death.
thanks kane.
Thanks for the diagram Ewan, much appreciated.
Mr Baker: perhaps I worded the question wrong. I am aware how to install fuses, but I wasnt certian as to the best location for them, I can see now that the way I asked the question may of sounded rather silly
hello david, no offense meant, just trying to save you a few quid in blowups or a few lost fights, depends which way you look at it.
by the way, Ive been asked by James Cooper to post to let everyone know that I have, this thursday in fact, recieved almost all of the things I was waiting for, and mentioned above. A part of the agreement of me getting it was that id post this, so true to my word,, if you could all ingnore the whole give me what I paid for 6 months ago thing, that would be nice.
there we go, everyone is friends again.
Sorry to jump in late on this discussion, but Im not quite clear on the position of the link in this circuit. I understand that speed controllers can suffer damage if they dont have anywhere to dump excess power, but Im not sure why putting the link on the positive side - directly in line with the fuses on Ewans diagram, if that is what you meant - would help matters.
A just think this: replace the 30 amp fuse to 40 amp, what happends then whit the electronize ?
i chud stand that , amp limit 90 amp and a temp sensor turn it off when it get to hot.
40a is fine, as ive said before, the limiting factor in a 30A elecronize is the relay at the moment. run in just 1 direction and 40A is not a problem, in fact I have run one at 70A spinning up a disk. it is good practice to put a link in the + side, but as kane said, it lets the fets discharge
Perhaps my A-level knowledge of physics is missing something subtle here but I thought that if the positive battery connection is isolated then no current can flow into either terminal.