How do they calculate hammer force?

I've seen people mentioning the force that their hammer weapon produces but an struggling to calculate my design: A spring hammer design.

As an example: 1000N tension spring. With 10kg hammer head and 50cm arm with fulcrum at 10cm.

Force applied to hammer is:
1000N x 0.1m / 0.4m = 0.25Nm

How can I calculate how much this accelerates my hammer assuming the hammer starts at 0 degrees and pivots to 180degrees.

I assume this takes one calculation to get force to 90degrees and then a different one to add in gravity as it falls.

Would be really grateful for some help.

Ps. these motor driven hammer "400kg down force" claims seem a little off. Are they just get the kgf/m and adding the force of the hammer head dropping under its own weight?

Thanks,
Dan

A hammer is a disk that doesn't make a full circle, so the calculations are the same.
But with the caveat that acceleration to a way lower rpm will make the available hitting power a lot less.

Thanks for your reply Maddox. But doesn't the weight of the head first need lifting as opposed to a disc which has momentum and is symmetrically weighted?

For power balance isn't an issue.
Balance is an issue for mechanical reliability.

On momentum. There is exactly no difference between the impact of a tooth from a disk or the impact of a simular sized hammerhead with the same speed and mass.

OK that's interesting. Do you have a link to the formula for spinners?

http://www.teamcosmos.com/ke/ke.shtml

Ah excellent thanks